# Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).

**Solution:**

The standard equation of a straight line is Ax + By + C = 0.

Equation of the line is (y - y_{1}) = [(y_{2} - y_{1}) / (x_{2} - x_{1})] (x - x_{1}) ------(1)

Given that line passes through (6, 0) and (2, -7)

∴ Substituting (x_{1}, y_{1}) = (6, 0) and (x_{2}, y_{2}) = (2,-7) in equation (1),

(y - y_{1}) = [(y_{2} - y_{1})/(x_{2} - x_{1})] (x - x_{1})

(y - 0) = [(-7 - 0)/ (2 - 6)] (x - 2)

y = (-7 / -4) (x - 2)

4y = 7x - 14

7x - 4y - 14 = 0

This is the required equation of the line which is in the general form.

## Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).

**Summary:**

The standard form of the equation of the line that passes through (6,0) and (2,-7) is 7x - 4y - 14 = 0.

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