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Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).
Solution:
The standard equation of a straight line is Ax + By + C = 0.
Equation of the line is (y - y1) = [(y2 - y1) / (x2 - x1)] (x - x1) ------(1)
Given that line passes through (6, 0) and (2, -7)
∴ Substituting (x1, y1) = (6, 0) and (x2, y2) = (2,-7) in equation (1),
(y - y1) = [(y2 - y1)/(x2 - x1)] (x - x1)
(y - 0) = [(-7 - 0)/ (2 - 6)] (x - 2)
y = (-7 / -4) (x - 2)
4y = 7x - 14
7x - 4y - 14 = 0
This is the required equation of the line which is in the general form.
Determine the standard form of the equation of the line that passes through (6,0) and (2,-7).
Summary:
The standard form of the equation of the line that passes through (6,0) and (2,-7) is 7x - 4y - 14 = 0.
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