Eliminate the parameter. x = square root of t, y = 4t + 1

Solution:

Given x = square root of t, y = 4t + 1

In order to eliminate the parameter ‘t’, we need to make substitutions

Let x = square root of t --- [a]

And , y = 4t + 1 --- [b]

x = √t ⇒ x² = t [by squaring on both sides]

Put t = x² in [b]

y = 4(x²) + 1

y = 4x² + 1

Hence, the parameter ‘t’ is eliminated

Eliminate the parameter. x = square root of t, y = 4t + 1

Summary:

The parameter in x = square root of t and y = 4t + 1 is eliminated i.e., y = 4x² + 1.