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Find 3x2 - y3 - y3 - z if x = 3, y = -2, and z = -5?
Solution:
3x2 - y3 - y3 - z [Given]
x = 3, y = -2, and z = -5
Now substitute the values in the given linear equation
= 3 (3)2 - (-2)3 - (-2)3 - (-5)
By further calculation
= 3 (9) - (-8) - (-8) + 5
So we get
= 27 + 8 + 8 + 5
= 48
Therefore, the value of 3x2 - y3 - y3 - z is 48.
Find 3x2 - y3 - y3 - z if x = 3, y = -2, and z = -5?
Summary:
3x2 - y3 - y3 - z if x = 3, y = -2, and z = -5 is 48.
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