Find a point on the line and the slope of the line.
We may use the general equation of the line to understand the examples.
Answer: The slope of the a line represented by c = ax + b is -b/a and one point on it is (0,c/b).
Let's understand the solution
Let the equation of a line be, ax + by = c, where a,b,c are constants
Slope of the line = (negative coefficient of x) / ( coeffecient of y )
slope = -b/a
Example 1, To find a point on the line, let us suppose x = 0
Therefore, y =c/b
So, a point on the line will be (0, c/b)
Suppose the equation of the line is 2x + 3 y = 5
Therefore, using the above example, and comparing this equation of line with the general equation i.e. ax + by = c
We get, a = 2, b = 3, c = 5
Thus, slope of this line = -b / a = -3/2
Point lying on it will be, (0, c / b) = (0, 5 / 3)