Find all values of x and y such that fx(x, y) = 0 and fy(x, y) = 0 simultaneously.
f(x, y) = 15x3 - 3xy + 15y3.
Solution:
Given: Function f(x, y) = 15x3 - 3xy + 15y3.
fx(x, y) ⇒ This means differentiate the function with respect to x
d/dx (f(x, y)) = 15(3)x2 - 3y
= 45x2 - 3y
Given that fx(x, y) = 0
⇒ 45x2 - 3y = 0
fy(x, y) ⇒ This means differentiate the function with respect to y
= d/dy (fy(x, y)) = 15(3)y2 - 3x
= 45y2 - 3x
Given that fy(x, y) = 0
⇒ 45y2 -3x = 0
As both functions occurr simultaneously, equate with each other
45x2 - 3y = 45y2 - 3x
45x2 - 45y2 = 3y - 3x
45(x2 - y2) = 3(x - y)
We know that (x2 - y2) = (x + y)(x - y)
15(x - y)(x + y) = (x - y)
x + y = 1/15
Thus, the values of x, y can be anything that sum up to 1/15.
Find all values of x and y such that fx(x, y) = 0 and fy(x, y) = 0 simultaneously.
f(x, y) = 15x3 - 3xy + 15y3.
Summary:
All the values of x and y such that fx(x, y) = 0 and fy(x, y) = 0 simultaneously can be anything that sum up to 1/15.
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