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# Find the area of a triangle with a base of 10 inches and altitude to the base of 16 inches.

**Solution:**

Base of the triangle = 10 inches

Altitude of the triangle = 16 inches

We know that,

Area of the triangle = 1/2 × b × h

Where b is the base, h is the altitude

Substituting the values

Area of the triangle = 1/2 × 10 × 16

By further calculation,

Area of the triangle = 80 inches^{2}

Therefore, the area of a triangle is 80 inches^{2}.

## Find the area of a triangle with a base of 10 inches and altitude to the base of 16 inches.

**Summary:**

The area of a triangle with a base of 10 inches and altitude to the base of 16 inches is 80 inches^{2}.

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