# Find the differential dy and evaluate dy for the given values of x and dx. y = √(1 - x), x = 0, dx = 0.02

**Solution:**

Given: The differential equation is y = √(1 - x)

Differentiating on both the sides

dy = 1/2√(1 - x) × (-1)dx

But given x = 0 and dx = 0.02

dy = 1/2(1 - 0) × (-1)0.02

dy = -1/2 × 0.02

dy = -0.01

Therefore, dy = -0.01 if y = √(1 - x), x = 0, dx = 0.02

## Find the differential dy and evaluate dy for the given values of x and dx.y = √(1 - x), x = 0, dx = 0.02

**Summary:**

If y = √(1 - x), x = 0, dx = 0.02 then dy = -0.01.

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