Find the distance between points p (-3, 4) and q (1, 6).

Solution:

Given points p (-3, 4) and q (1, 6)

We know that the distance between two points is given by d

d = √(x₂ - x₁)² + (y₂ - y₁)²

Here, x₁ = -3, y₁ = 4; x₂ = 1; y₂ = 6

d = √(1 - (-3))² + (6 - 4)²

d = √(1 + 3)² + (6 - 4)²

d = √4² + 2²

d = √16 + 4

d = √20 units

The distance between two given points is d = √20 units

Find the distance between points p (-3, 4) and q (1, 6).

Summary:

The distance between points p (-3, 4) and q (1, 6) is d = √20 units