Find the equation in standard form of the line passing through the points (2, -3) and (4, 2)
Solution:
The standard form of an equation of line is given by:
y = mx + c
The point slope form is
y - y1 = m (x - x1)
Where m is the slope,
(x1, y1) is the point through which the given line passes.
The slope formula is given by:
m = (y2 - y1) / (x2 - x1)
Substituting the values
m = (2 - (-3)) / (4 - 2)
m = 5/2
So we get
y - (-3) = 5/2 (x - 2)
By using the distributive property
y + 3 = 5/2 (x - 2)
Multiplying 2 on both sides, we get
2y + 6 = 5x - 10
Subtracting 6 on both sides, we get
2y + 6 - 6 = 5x - 10 - 6
2y = 5x - 16
On rearranging, we get
5x - 2y = 16
Therefore, the equation in standard form is 5x - 2y = 16.
Find the equation in standard form of the line passing through the points (2, -3) and (4, 2)
Summary:
The equation in standard form of the line passing through the points (2, -3) and (4, 2) is 5x - 2y = 16.
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