Find the equation of the circle whose center = ( 5, 6) and radius = 3?

Solution:

Given: Center of the circle (5, 6) and radius = 3

We know that the equation of a circle whose center is (h,k) and radius is r can be given as 

(x - h)² + (y - k)² = r² --- (1)

Substitute the values h = 5 , k = 6 and r = 3 in the equation(1)

(x - 5)² + (y - 6)² = 3²

x² - 10x + 25 + y² - 12y + 36 = 9

x² + y² - 10x - 12y + 52 = 0

Thus the equation of the circle with given data is x² + y² - 10x - 12y + 52 = 0

Find the equation of the circle whose center = ( 5, 6) and radius = 3?

Summary:

The equation of the circle with centre (5, 6) and radius = 3 is x² +y² - 10x - 12y + 52 = 0.