# Find the rate of change of the function h(x) = 2^{x} on the interval 2 ≤ x ≤ 4?

**Solution:**

Consider f as the function defined on the interval a ≤ x ≤ b, so the rate of change of function A(x) is denoted as

A(x) = [f(b) - f(a)]/[b - a]

When x = 2

h(2) = 2^{2} = 4

When x = 4

h(4) = 2^{4} = 16

From the definition of rate of change of function

A (x) = [h(4) - h(2)]/[4 - 2]

We know that,

h(2) = 4 and h(4) = 16

A(x) = [16 - 4]/2

A(x) = 12/2

A(x) = 6

Therefore, the rate of change of function is 6.

## Find the rate of change of the function h(x) = 2x on the interval 2 ≤ x ≤ 4?

**Summary:**

The rate of change of the function h(x) = 2x on the interval 2 ≤ x ≤ 4 is 6.