Find the sum of 7a3 + 14a + 12 and -6a3 + 12a2 - 7.
Solution:
We have to find the sum of 7a3 + 14a + 12 and -6a3 + 12a2 - 7.
7a3 + 14a + 12 + (-6a3 + 12a2 -7)
= 7a3 + 14a + 12 - 6a3 + 12a2 -7
By rearranging the terms
= 7a3 - 6a3 + 12a2 + 14a + 12 - 7
So we get
= a3 + 12a2 + 14a + 5
Therefore, the sum is a3 + 12a2 + 14a + 5.
Find the sum of 7a3 + 14a + 12 and -6a3 + 12a2 - 7.
Summary:
The sum of 7a3 + 14a + 12 and -6a3 + 12a2 - 7 is a3 + 12a2 + 14a + 5.
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