Given a(n) = a + d(n - 1), find the value of a and d for the arithmetic sequence 3, 5, 7, 9, …?
Solution:
Given: Series is 3, 5, 7, 9, …..
On observing we got that the series is an Arithmetic Progression
An Arithmetic Progression is a sequence of numbers in which each number differs from the preceding one by a constant quantity.
Eg: 1, 2, 3, 4, 5
Here the difference between every number is 1
Therefore, this is in AP.
Eg: 2, 4, 6, 8
Here the difference between every number is 2
Therefore, this is in AP.
Now,
In the given series we have 3, 5, 7, 9…
Here the difference between every number is 2
Therefore, it is in AP
Also given a formula a(n) = a + d(n - 1)
Here a is denoted for the first term of an AP and d is denoted for the common difference
For the given sequence we get,
a = 3 and d = 2
Given a(n) = a + d(n - 1), find the value of a and d for the arithmetic sequence 3, 5, 7, 9, …?
Summary:
For the given arithmetic series 3, 5, 7, 9… the values of a and d are 3 and 2.
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