Given the exponential equation 3x = 27, what is the logarithmic form of the equation in base 10?
Solution:
Given: Exponential equation 3x = 27
We need to convert the above equation in logarithmic form,
First apply log both sides with base 10
log103x = log1027
We know, log am = m loga
x log103 = log1027
Now, divide by log103 both sides
x = log1027 / log103
Therefore, the logarithmic form of the equation in base 10 is x = log1027 / log103.
Given the exponential equation 3x = 27, what is the logarithmic form of the equation in base 10?
Summary:
Given the exponential equation 3x = 27, the logarithmic form of the exponential equation in base 10 is x = log1027 / log103.
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