How many solutions (x, y) are there to the system of equations above 2x + 6y = 5 and x + 3y = 2

Solution:

The given system of equations are

2x + 6y = 5 --- (1)

x + 3y = 2 --- (2)

Equation (2) can be written as

x = 2 - 3y --- (3)

Substituting it in equation (1)

2 (2 - 3y) + 6y = 5

Using the multiplicative distributive property

4 - 6y + 6y = 5

So we get

0 = 5 - 4

0 = 1

Therefore, the system of equations has no solutions.

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How many solutions (x, y) are there to the system of equations above 2x + 6y = 5 and x + 3y = 2

Summary:

The system of equations above 2x + 6y = 5 and x + 3y = 2 has no solutions.