How many x-intercepts does the graph of y = -(x + 1)2 - 2 have?
For a function f(x), x-intercept are the points of the form (a, 0) that gives the value of the function f(x) zero.
Answer: The graph of y = -(x + 1)2 - 2 has no x-intercept.
We will substitute 0 for y in the given equation to find the x-intercept.
0 = -(x + 1)2 - 2
(x + 1)2 = - 2
The square of any real number cannot be negative. So, this is not possible.