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# How to write the slope-intercept form of the equation of the line described; (-2, -1) parallel to y = -3/2x - 1?

Given y= (-3/2)x - 1 and point (-2, -1)

The slope of a line is a number that measures its "steepness", usually denoted by the letter m. It is the change in y for a unit change in x

The slope of the given equation is -3/2

Since the lines are parallel, their slopes will be the same. m_{1} = m_{2}

Hence, the slope required is also -3/2

Let that line equation be y = mx + b where m = -3/2

Since the point lies on it, it must satisfy it

So, -1 = (-3/2)(-2) + b

-1 = 3 + b

b= -3 - 1

b = -4

Therefore, the equation of line is y = -3/2x -4

## How to write the slope-intercept form of the equation of the line described; (-2, -1) parallel to y = -3/2x - 1?

**Summary:**

The slope intercept form of the equation of the line described; (-2, -1) parallel to y = -3/2x - 1 is y = -3/2x -4

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