# If Diagonals of a rhombus is 10 cm and 24 cm find its perimeter.

A rhombus can be defined as a diamond-shaped quadrilateral that has all four sides equal.

## Answer: If Diagonals of a rhombus is 10 cm and 24 cm then perimeter of the rhombus is 52 cm.

Let's find the perimeter of the rhombus

**Explanation:**

Let's draw a diagram of the rhombus with the diagonals 10cm and 24cm

Here, AC = 24 cm and BD = 10 cm, therefore, AO = 12 cm and BO = 5 cm.

Now to find the perimeter, we need the length of AB.

Let’s find AB using the pythagoras theorem in ABC,

AB^{2} = AO^{2} + OB^{2}

AB^{2 }= 12^{2 }+ 5^{2}

AB^{2 }= 144 + 25

AB^{2 }= 169

AB = √169

AB = 13 cm

Since the length of one side of the rhombus is AB = 13cm, perimeter of the rhombus, P = 4 × side of a rhombus

P = 4 × AB

P = 4×13 = 52 cm