If f(x) = x2 + 1 g(x) = 5 - x. (f + g)(x) = ?
Solution:
Given, functions are f(x) = x2 + 1
g(x) = 5 - x
We have to find (f + g)(x).
(f + g)(x) = f(x) + g(x)
= x2 + 1 + 5 - x
On rearranging,
(f + g)(x) = x2 - x + (5 + 1)
= x2 - x + 6.
Therefore, (f + g)(x) = x2 - x + 6.
Example:
If f(x) = 3x2 + 1 g(x) = 15 - x. (f + g)(x) =?
Solution:
Given, f(x) = 3x2 + 1
g(x) = 15 - x
We have to find (f + g)(x).
(f + g)(x) = f(x) + g(x)
= 3x2 + 1 + 15 - x
On rearranging,
(f + g)(x) = 3x2 - x + (15 + 1)
= 3x2 - x + 16.
Therefore, (f+g)(x) = 3x2 - x + 16.
If f(x) = x2 + 1 g(x) = 5 - x. (f + g)(x) = ?
Summary:
If f(x) = x2 + 1 g(x) = 5 - x. (f + g)(x) = x2 - x + 6.
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