If s(x) = 2x² + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =

Solution:

Given are two functions s(x) and t(x).

s(x) = 2x² + 3x - 4

t(x) = x + 4

Substitute the value of s(x) and t(x) in s(x).t(x)

s(x) · t(x) = (2x² + 3x - 4) (x + 4)

By further calculation

s(x) · t(x) = 2x³ + 8x² + 3x² + 12x - 4x - 16

So we get

s(x) · t(x) = 2x³ + 11x² + 8x - 16

Therefore, s(x) · t(x) = 2x³ + 11x² + 8x - 16.

If s(x) = 2x² + 3x - 4, and t(x) = x + 4 then s(x) · t(x) =

Summary:

If s(x) = 2x² + 3x - 4, and t(x) = x + 4 then s(x) · t(x) = 2x³ + 11x² + 8x - 16.