If s(x) = 2x² + 3x - 4, and t(x) = x + 4 then s(x) · t(x) = ?

We will use the concept of functions to solve this.

Answer: If s(x) = 2x² + 3x - 4, and t(x) = x + 4 then s(x) · t(x) = 2x³ + 11x² + 8x - 16.

Let us solve it step by step.

Explanation:

Given:

s(x) = 2x² + 3x - 4

t(x) = x + 4

Both s(x) and t(x) are functions of x and dependent on x. 

s(x) · t(x) = (2x² + 3x - 4)(x + 4)

= 2x³ + 3x² - 4x + 8x² + 12x - 16

= 2x³ + 11x² + 8x - 16

Thus, if s(x) = 2x² + 3x - 4 and t(x) = x + 4 then, s(x) · t(x) = 2x³ + 11x² + 8x - 16.