# If you are solving y^{2} + 2y = 48 by completing the square, the next line would be

**Solution:**

Given, y^{2} + 2y = 48

We have to find the next step while solving y^{2} + 2y = 48.

We need to complete the square to make LHS a trinomial.

Now, y^{2} + 2y + c = 48

To find c, we multiply the coefficient of y by -(1/2) and square it to get the third term.

The coefficient of y is 2. Thus 2 ×-(1/2) 1 and squaring it we get 1^{2}

Thus the trinomial is y^{2} + 2y+1^{2}

We know, (a + b)^{2} = a^{2} + 2ab + b^{2}

(y+1)^{2} = 48 +1

(y+1)^{2} = 49

Therefore, the next step in solving is making the LHS a trinomial.

## If you are solving y^{2} + 2y = 48 by completing the square, the next line would be

**Summary:**

If you are solving y^{2} + 2y = 48 by completing the square, the next line would be y^{2} + 2y - 48 = 0.

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