In circle O, ST is a diameter. What must be the value of x?

Solution:

Given, ST is a diameter.

We have to find the value of x.

Since ST is a diameter, ∠TOS = 180°

Now, ∠TOU + ∠UOR + ∠ROS = ∠TOS

From the figure,

(3x - 14)° + (3x - 14)° + (2x + 8)° = 180°

3x + 3x + 2x - 14 - 14 + 8 = 180

8x - 20 = 180

8x = 180 + 20

8x = 200

x = 200/8

x = 25

Therefore, the value of x is 25.

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In circle O, ST is a diameter. What must be the value of x?

Summary:

In circle O, ST is a diameter. The value of x must be 25.