Segments RT and SU are diameters of circle O. What is m of SRT?

Solution:

Minor arc ST = ∠SOT by central angle

∠SOT = ∠ROU (vertical angles)

We know that

∠ROU = 90°

∠SOT = 90°

minor arc ST= 90°

The sum of Major arc and Minor arc is 360°

Minor arc ST + Major arc RST = 360°

Major arc RST = 360 - 94 = 266°

Therefore, m of SRT is 266°.

Segments RT and SU are diameters of circle O. What is m of SRT?

Summary:

Segments RT and SU are diameters of circle O. m of SRT is 266°.