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# Solve for b_{2} in A = 1/2 h(b_{1 }+ b_{2}), if A = 16, h = 4, and b_{1} = 3.

**Solution:**

Given A = 1/2 h(b\(_1\)_{ }+ b\(_2\))

A = 16, h = 4, and b\(_1\) = 3

Substitute the values in the given linear equation

A = 1/2 h(b\(_1\)_{ }+ b\(_2\)) ⇒ 16 = 1/2(4)(3 + b\(_2\))

⇒ 16(2) = 4(3 + b\(_2\))

⇒ 32 = 4(3 + b\(_2\))

⇒ 8 = 3 + b\(_2\)

⇒ b\(_2\) = 8 - 3 = 5

b\(_2\)= 5

## Solve for b_{2} in A = 1/2 h(b_{1 }+ b_{2}), if A = 16, h = 4, and b_{1} = 3.

**Summary:**

By solving A = 1/2 h(b_{1 }+ b_{2}), if A = 16, h = 4, and b_{1} = 3, then b_{2 }= 5.

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