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# Solve the following system of equations 3x + 2y - 5 = 0 and x = y + 10

**Solution:**

Given, the linear equations are

3x + 2y - 5 = 0 --- (1)

x = y + 10 --- (2)

Now substitute (2) in (1)

⇒ 3(y + 10) + 2y - 5 = 0

⇒ 3y + 30 + 2y -5 = 0

⇒ 3y + 2y + 25 = 0

⇒ 5y + 25 = 0

⇒ 5y = -25

⇒ y = -5

To find the value of x put y = -5 in (2)

⇒ x = -5 + 10

⇒ x = 5

Therefore, the solution is (5, -5).

## Solve the following system of equations 3x + 2y - 5 = 0 and x = y + 10

**Summary:**

The following system of equations 3x + 2y - 5 = 0 and x = y + 10 has solution (5, -5).

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