# Solve the system of equations using substitution. y = 2x - 10 and y = 4x - 8

**Solution:**

The given equations are

y = 2x - 10 …. (1)

y = 4x - 8 …. (2)

Equation (1) can be written as

2x = y + 10

x = (y + 10)/2 …. (3)

Substituting equation (3) in (2)

y = 4 (y + 10)/2 - 8

y = 2(y + 10) - 8

Using the multiplicative distributive property

y = 2y + 20 - 8

y - 2y = 12

-y = 12

y = -12

Substituting the value of y in equation (1)

-12 = 2x - 10

-12 + 10 = 2x

2x = -2

x = -1

Therefore, the solution to the system of equations is (-1, -12).

## Solve the system of equations using substitution. y = 2x - 10 and y = 4x - 8

**Summary:**

Solving the system of equations using substitution y = 2x - 10 and y = 4x - 8 the solution is (-1, -12).

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