# Solve x^{2} = 5 - x using the quadratic formula. what are the values of x?

**Solution:**

Given that:

x^{2} = 5 - x

It can be written in arranged form as:

x^{2} + x - 5 = 0

The formula for the standard form of quadratic equation ax^{2} + bx + c = 0 is written as

x = [−b ± √(b^{2} − 4ac)] / 2a

From the given equation we know that

a = 1

b = 1

c = -5

Substituting it in the formula

x = [ -(1) ± √{(1)^{2} - 4(1)(-5)} ] / 2(1)

x = [ -1 ± √{1 + 20} ] / 2

By further calculation

x = [ -1 ± √21 ] / 2

Therefore, the values of x are [-1 + √21] / 2 and [ -1 - √21 ] / 2.

## Solve x^{2} = 5 - x using the quadratic formula. what are the values of x?

**Summary: **

By solving x^{2} = 5 - x using the quadratic formula, the values of x are [-1 + √21] / 2 and [ -1 - √21 ] / 2.