Solve x² + 9x + 20. x = 2, x = 10, x = −2, x = −10 x = −5, x = −4, x = 5, x = 4

The above quadratic equation is in the form of ax² + bx + c

Answer: The quadratic equation is satisfied when x = -5, and x = -4

Substituting the given values of 'x' in the quadratic equation, we will check the values for which the equation will be equal to 0.

Explanation:

f(x) = x² + 9x + 20

If x = 2, (2)² + 9(2) + 20 = 4 + 18 + 20 = 42

If x = 10, (10)² + 9(10) + 20 = 100 + 90 + 20 = 210

If x = -2, (-2)² + 9(-2) + 20 = 4 - 18 + 20 = 6

If x = -10, (-10)² + 9(-10) + 20 = 100 - 90 + 20 = 30

If x = -5, (-5)² + 9(-5) + 20 = 25 - 45 + 20 = 0

If x = -4, (-4)² + 9(-4) + 20 = 16 - 36 + 20 = 0

If x = 5, (5)² + 9(5) + 20 = 25 + 45 + 20 = 90

If x = 4, (4)² + 9(4) + 20 = 16 + 36 + 20 = 76

Therefore, after substituting the values of 'x', we get the solution of the quadratic equation when x = -5, and when x = -4