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# Suppose a bag contains 4 white chips and 6 black chips. What is the probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip?

**Solution:**

In the bag there are 4 + 6 = 10 chips

⇒. 4 white chips and 6 black chips

Probability that the first chip chosen is white is 4/10 = 2/5

Now there is one white chip less in the bag

There are 9 chips out of which 3 are white

Probability that the second chip chosen is white is 3/9 = 1/3

By multiplying the probabilities, we will be able to find the probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip

= 2/5 × 1/3

= 2/15

Therefore, the probability is 2/15.

## Suppose a bag contains 4 white chips and 6 black chips. What is the probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip?

**Summary:**

Suppose a bag contains 4 white chips and 6 black chips. The probability of randomly choosing a white chip, not replacing it, and then randomly choosing another white chip is 2/15.

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