The equation of the circle whose center is at (2, 1) and radius is 3 is
Solution:
Given, center of the circle = (2,1)
Radius, r = 3 units.
We have to write the equation of the circle.
The general equation of the circle is given by (x - h)2 + (y - k)2 = r2
Where, (h,k) is the center
r is the radius
Here, (h,k) = (2,1) and r = 3
So, (x - 2)2 + (y - 1)2 = (3)2
(x - 2)2 + (y - 1)2 = 9
Therefore, the equation of the circle is (x - 2)2 + (y - 1)2 = 9.
The equation of the circle whose center is at (2, 1) and radius is 3 is
Summary:
The equation of the circle whose center is (2,1) and radius is 3 is (x - 2)2 + (y - 1)2 = 9.
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