The LCM of two numbers is 2516 and the square root of their HCF is 2, find product of the two numbers
Answer: The product of the two numbers, whose LCM is 2516 and the square root of their HCF is 2 is 629
Lets see how to solve it.
Explanation:
Given that the LCM of two numbers is 2516 and the square root of their HCF is 2
We know that the formula of LCM for two numbers a and b is LCM (a, b) = (a × b) / HCF (a, b)
The square root of the hcf of the two numbers is 2
So, the HCF of the two numbers = 2 × 2 = 4
Hence, (a × b) = LCM (a, b) / HCF (a, b)
= 2516 / 4
= 629
The product of the two numbers is 629