The perimeter of square JKLM is 48 units. The length of J K is x + 3. What is the value of x?
6, 9, 12, 15

finding the perimeter of the square with side x+3 units

Solution:

Given perimeter of square, JKLM is 48 units

The length of J K is x + 3

Let ‘a’ be the length of a square, then its perimeter can be given as ‘4a’ since all its four lengths are equal.

Equate the perimeter with the given value

Perimeter = 4(x + 3) = 48

⇒ 4(x + 3) = 48

⇒ x + 3 = 48/4 = 12

⇒ x = 12 - 3

⇒ x = 9

Therefore, the value of x is 9

The perimeter of square JKLM is 48 units. The length of J K is x + 3. What is the value of x?

Summary:

The perimeter of square JKLM is 48 units. The length of J K is x + 3. The value of x is 9.

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