# The sum of three consecutive multiples of 8 is 888.find the multiples.

Let us find the multiples of 8 satisfying the given condition.

## Answer: The three consecutive multiples are 288, 296, and 304.

Let us simplify the given problem by nature of multiples of a number.

**Explanation:**

The multiples of 8 are in the format of 8n.

Let the three consecutive multiples of 8 are 8n - 8, 8n, and 8n + 8

Given that, the sum of these multiples is 888.

⇒ 8n - 8 + 8n + 8n + 8 = 888

⇒ 8n + 8n + 8n = 888

⇒ 24n = 888

⇒ n = 888 / 24

⇒ n = 37

⇒ 8n = 296

The multiples of 8 are:

- 8n - 8 = 296 - 8 = 288
- 8n = 296
- 8n + 8 = 296 + 8 = 304

Thus, the three consecutive multiples of 8 are 288, 296, and 304.