# What are the Solutions of the Equation 4x^{2} + 3x = 24 – x?

We will be simplifying the equation to solve it.

## Answer: The solutions of the equation 4x^{2} + 3x = 24 – x are -3, and 2.

Let's solve this step by step to find the zeros of 4x^{2} + 3x = 24 – x.

**Explanation:**

Given that, 4x^{2} + 3x = 24 – x.

Simplify the equation first,

⇒ 4x^{2} + 4x - 24 = 0

Divide by 4 on both sides,

⇒x^{2} + x - 6 = 0

We have to find the roots of the equation.

Let, f(x) = x^{2} + x - 6

= x^{2} + 3x - 2x - 6

= x^{2} - 2x + 3x - 6

= x(x - 2) + 3(x - 2)

= (x - 2)(x + 3)

(x + 3) = 0 and (x^{ }- 2) = 0

x = -3 and x^{ }= 2

You can verify your answer using Cuemath's roots calculator.

### Thus, the solutions of the equation 4x^{2} + 3x = 24 – x are -3, 2.

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