What are the x-coordinates of the solutions to this system of equations?
x2 + y2 = 100, y = x + 2
Solutions:
x2 + y2 = 100 , y = x + 2
Given system of equations:
x2 + y2 = 100 --- (1)
y = x + 2 --- (2)
Replace y = x + 2 in equation 0 gives
x2 + (x + 2)2 = 100
(a + b)2 = a2 + 2ab + b2
Changes above equation to
x2 + x2 + 4x + 4 = 100
2x2 + 4x = 100 - 4
2x2 + 4x = 96
Dividing by 2 on both sides so that the equation reduces to simplified from
x2 + 2x = 48
x2 + 2x - 48 = 0
On solving by factorization method
x2 + 8x - 6x - 48 = 0
x(x + 8) - 6(x + 8) = 0
What are the x-coordinates of the solutions to this system of equations?
x2 + y2 = 100, y = x + 2
Summary:
The x-coordinates of the solutions to this system of equations x2 + y2 = 100 , y = x + 2 are 6, -8.
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