# What is the 22^{nd} term of the arithmetic sequence where a_{1 }= 8 and a_{9} = 56?

**Solution:**

The nth term of an arithmetic sequence whose first term is a_{1} and common difference is d is

⇒ a_{1} + (n - 1)d

It is given that

a_{1} = 8 and a_{9} = 56

We know that

a_{9} = a_{1} + (9 - 1)d

8 + 8d = 56

8d = 56 - 8

8d = 48

d = 6

Now we have to find the 22^{nd} term

a_{22} = a_{1} + (22 - 1)d

Substituting the values

a_{22} = 8 + (21)(6)

a_{22} = 8 + 126

So we get,

a_{22} = 134

Therefore, the 22^{nd} term is 134.

## What is the 22^{nd} term of the arithmetic sequence where a_{1} = 8 and a_{9} = 56?

**Summary:**

The 22^{nd} term of the arithmetic sequence where a_{1 }= 8 and a_{9} = 56 is 134.

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