# What is the 50th term of the sequence that begins − 6, 0, 6, 12, ...?

An arithmetic progression is a sequence in which the difference between a pair of consecutive numbers is equal.

## Answer: The 50^{th} term of the sequence that begins with - 6 is 288.

Let's solve for 50^{th} term of the sequence that begins − 6, 0, 6, 12, ...

**Explanation:**

The given sequence is − 6, 0, 6, 12, ...

It is in arithmetic progression as the common difference between all consecutive numbers is 6.

Let a_{1} be the first term and d be the common difference.

Therefore, a_{1} = - 6 and d = 6

For 50^{th} term, a_{50} = a_{1} + (n - 1) d

= - 6 + (50 - 1) 6

= - 6 + 49 × 6

= - 6 + 294

= 288