# What is the area of a sector of a circle with a radius of 8 inches and an angle of 45 degrees.?

The area of the sector is defined as the area of the part of the circle, defined by the angle of the sector.

## Answer: The area of the sector of the circle with 45 degrees angle and 8-inch radius is 25.12 inch^{2}.

Go through the explanation to understand better.

**Explanation:**

**Area of Sector of the circle:**

The area of the sector is defined as the area enclosed by the angle made within the circle.

Area of circle = πr^{2} , where r is the radius of the circle.

Area of a sector of the circle = θ/360 × πr^{2}, where θ is the angle made by the sector.

The area made by the sector of 45 degrees = 45/360× πr^{2}

Area of the sector = 1/8× πr^{2 }= 1/8 × π(8)^{2} = 8π = 25.12 inch^{2} [ Since, radius = 8 inch]