What is the axis of symmetry for f(x) = 2x² + 8x + 8?

Solution:

Given that: f(x) = 2x² + 8x + 8

Let y = 2x² + 8x + 8

⇒y = 2[x² + 4x +4]

⇒y = 2[(x + 2)²]

⇒(x + 2)² = (1/2)y

⇒(x + 2)² = (1/2)(y - 0)

It is of the form (x - h)² = 4a(y - k) is a parabola whose vertex is at (-2, 0)

Therefore, the axis of symmetry is x = -2

What is the axis of symmetry for f(x) = 2x² + 8x + 8?

Summary:

The axis of symmetry for f(x) = 2x² + 8x + 8 is x = - 2