What is the center of a circle represented by the equation (x + 9)2 + (y + 6)2 = 102
Solution:
We know that
The equation of a circle is written as
(x - h)2 + (y - k)2 = a2
Where (h, k) is the center and a is the radius of the circle.
(x + 9)2 + (y + 6)2 = 102 (Given)
From the equation, the center of the circle is (-9, -6)
The radius of the circle is 10.
In general form, the equation can be written as
x2 + 18x + 81 + y2 + 12y + 36 = 100
x2 + y2 + 18x + 12y + 17 = 0
Therefore, the centre of the circle is (-9, -6).
What is the center of a circle represented by the equation (x + 9)2 + (y + 6)2 = 102
Summary:
The center of a circle represented by the equation (x + 9)2 + (y + 6)2 = 102 is (-9 ,-6).
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