What is the line of symmetry for the parabola whose equation is y = 3x² + 24x - 1?

Solution:

Given: Equation of parabola is y = 3x² + 24x - 1

We know that standard form of quadratic equation y = ax² + bx + c --- [a]

Then the axis of symmetry is given by: x = -b/2a --- [b]

On comparing with [a] we have; a = 3, b = 24 c = -1

Substitute in [b] we have x = -24/2(3)

= -24/6

= -4

Therefore, the line of symmetry for the parabola is, x = -4

What is the line of symmetry for the parabola whose equation is y = 3x² + 24x - 1?

Summary:

The line of symmetry for the parabola whose equation is y = 3x² + 24x - 1 is x = -4.