# What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

**Solution:**

A sequence in which the ratio between two consecutive terms is the same is called a geometric sequence.

The geometric sequence given is 4, 8, 16, 32, ...

Here a_{1} = 4

a_{n} = nth term

r = 8/4 = 2

The formula is a_{n} = a.r^{n - 1}

Where a is the first term

n is the number of terms

r is the common ratio

Substituting the values

a_{n} = 4(2)^{n - 1}

Therefore, the nth term is a_{n} = 4(2)^{n - 1}.

## What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

**Summary:**

The nth term of the geometric sequence 4, 8, 16, 32, ... is a_{n} = 4(2)^{n - 1}.

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