# What is the radius of a circle whose equation is (x + 5)^{2} + (y - 3)^{2} = 4^{2}?

2 units, 4 units, 8 units, 16 units

**Solution:**

The standard center radius equation of a circle is (x - h)^{2} + (y - k)^{2} = r^{2}

Where (h, k) are the coordinates of center and r is the radius of the circle

Given: (x + 5)^{2} + (y - 3)^{2} = 4^{2}

Comparing it with the standard equation

(h, k) = (-5, 3)

Radius r^{2} = 4^{2}

r = 4 units

Therefore, the radius of the circle is 4 units.

## What is the radius of a circle whose equation is (x + 5)^{2} + (y - 3)^{2}= 4^{2}?

**Summary:**

The radius of a circle whose equation is (x + 5)^{2} + (y - 3)^{2} = 4^{2} is 4 units.

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