# What is the range of the function f(x) = 3x − 12 for the domain {-2, 2}?

We will use the concept of range and domain monotonicity of function to find the required range.

## Answer: Range of function f(x) = 3x − 12 for the domain { - 2, 2 } is equal to { -18, -6 }

Let's look into the solution

**Explanation:**

Given: f(x) = 3x − 12

f^{'}(x) = 3 ( Differentiating both the sides with respect to x )

Since f^{'}(x) is always positive hence f ( x ) is increasing function always.

Therefore f(-2) will have minimum value and f(2) will have maximum value in the domain { - 2, 2 }

Also, range of a function is defined as the possible outputs we can have for a given set of inputs.

Thus, to calculate the range for the given domain { - 2, 2 }, we will calculate the values of f(-2) and f(2) using f(x) = 3x − 12,

⇒ f(-2) = 3(-2) -12 = -18

⇒ f(2) = 3(2) - 12 = -6