What is the remainder when (x³ - 6x² - 42x + 79) is divided by (x + 5)?

Solution:

Given, f(x) = x³ - 6x² - 42x + 79

By long division,

Therefore, the remainder is 14.

What is the remainder when (x³ - 6x² - 42x + 79) is divided by (x + 5)?

Summary:

The remainder when (x³ - 6x² - 42x + 79) is divided by (x + 5) is 14.