Which of the following is one of the two binomial factors of 6s² + 40s - 64?
s + 10, 2s - 16, 6s - 12, 3s - 4

Solution:

6s² + 40s - 64 = 0 [Given]

We have to find the two binomial factors

a = 6, b = 40 and c = -64

Substituting it in the formula

x = [-b ± √(b² - 4ac)]/2a

x = [-40 ± √(40² - 4 × 6 × -64)]/2 × 6

By further calculation

x = [-40 ± √(1600 + 1536)]/12

x = [-40 ± √(1600 + 1536)]/12

x = [-40 ± √3136]/12

So we get

x = [-40 ± 56]/12

x = (- 40 + 56)/12 and x = (-40 - 56)/12

x = 16/12 and x = -96/12

x = 4/3 and x = -8

Therefore, (3s - 4) and (s - 8) are the two binomial factors of 6s²+ 40s -64.

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Which of the following is one of the two binomial factors of 6s² + 40s - 64? s + 10, 2s - 16, 6s - 12, 3s - 4

Summary:

The two binomial factors of 6s² + 40s - 64 are (3s - 4) and (s - 8).