# Which of the following points lies on the line whose equation is y = 2x - 3?

(0, 3), (1, -1), (-1, 4)

**Solution:**

The equation is a straight line with a slope of 2 and an x-intercept of 3/2. To prove that a point lies on the line, coordinates of the point should satisfy the equation.

1. To verify the point (0, 3) lies on the line?

y = 2x - 3

Substituting x = 0 in the equation we get,

y = 2(0) - 3 = -3

Hence (0,3) is not the point that lies on the equation.

2. Let us check whether (1, -1) lies on the line?

Substituting x = 1 in the equation we get

y = 2(1) - 3 = -1

By putting x = 1 the value of y obtained is -1. Hence Point (1, -1) does lie on the line.

3. The next point to check is (-1, 4). So let us substitute x = -1 into the equation and we have

y = 2(-1) - 3 = -5

Hence (-1, 4) does not lie on the line as for x = -1 y = -5 which is not the desired result.

Therefore the point which lies on the line with the equation y = 2x - 3 is (1, -1)

## Which of the following points lies on the line whose equation is y = 2x - 3?

**Summary:**

The point that lies on the line whose equation is y = 2x - 3 is (1, -1)