# Which of the following polynomials has zeros at x = –4 and x = 7?

# 4x^{2} - 7x - 11, 4x^{2} - 49 ,7x^{2} - 4x + 28, x^{2} - 3x - 28

All the values of 'x' that makes the polynomial equal to zero are called as zeroes of a polynomial.

## Answer: x^{2} - 3x - 28 has zeros at x = –4 and x = 7.

Let us proceed step by step.

**Explanation:**

Given: Zeroes are -4 and 7

As we know that a polynomial of two degrees can be written as:

x^{2} - (sum of zeroes) x + (product of zeroes)

Sum of zeroes = 3

Product of zeroes = -28

Hence we can write the polynomial using two given zeros as:

x^{2} - 3x - 28