Which of the following polynomials has zeros at x = – 4 and x = 7?
4x2 - 7x - 11, 4x2 - 49, 7x2 - 4x + 28, x2 - 3x - 28
Answer: x2 - 3x - 28 has zeros at x = – 4 and x = 7.
Let us proceed step by step.
Given: Zeroes are -4 and 7
As we know that a polynomial of two degrees can be written as:
x2 - (sum of zeroes) x + (product of zeroes)
Sum of zeroes = 3
Product of zeroes = - 28
Hence we can write the polynomial using two given zeros as:
x2 - 3x - 28