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# Which shows one way to determine the factors of 12x^{3} - 2x^{2} + 18x - 3 by grouping?

2x^{2}(6x - 1) + 3(6x - 1)

2x^{2}(6x - 1) - 3(6x - 1)

6x(2x^{2} - 3) - 1(2x^{2} - 3)

6x(2x^{2} + 3) + 1(2x^{2} + 3)

**Solution:**

Factoring polynomials are one in many ways. Factoring by grouping refers to the grouping of the terms having common factors before factoring.

The given expression is

12x^{3} - 2x^{2} + 18x - 3

By grouping the first two terms and last two terms

= (12x^{3} - 2x^{2}) + (18x - 3)

Here 2x^{2} is common in the first two terms and 3 is common in the last two terms

= 2x^{2} (6x - 1) + 3 (6x - 1)

Therefore, 2x^{2}(6x - 1) + 3(6x - 1) shows one way to determine the factors.

## Which shows one way to determine the factors of 12x^{3} - 2x^{2} + 18x - 3 by grouping?

2x^{2}(6x - 1) + 3(6x - 1)

2x^{2}(6x - 1) - 3(6x - 1)

6x(2x^{2} - 3) - 1(2x^{2} - 3)

6x(2x^{2} + 3) + 1(2x^{2} + 3)

**Summary:**

2x^{2}(6x - 1) + 3(6x - 1) is one way to determine the factors of 12x^{3} - 2x^{2} + 18x - 3 by grouping.

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